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How many ammonium ions and how many sulfate ions are present in an 0.370 mol sample of (nh4)2so4?

1 Answer

5 votes
The number of ions will be determined by the molecule component. In this question, (nh4)2so4 contain two ammonium ion from (NH4)2 and one sulfate ion from SO4. Then the calculation would be:

Ammonium ion: 2/1 x 0.37 mol= 0.74 mol
Sulfate ion: /1 x 0.37 mol= 0.37 mol
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