First solution can be:
 L = S+4
 8L = 12S-24 substitute for L:
 8(S+4) = 12S-24
 8S+32 = 12S-24 add 24 on both sides and subtract 8S on both sides, and you get:
 56 = 4S rewrite to get the unknown on the left:
 4S = 56
 S = 14 this is the cost of a small bottle.
  
 Other solution can be like this:
 Let cost of each small bottle be S
 The cost of each large bottle = S + 4
 We then get: 8(S + 4) = 12S - 24
 8S - 12S = - 24 - 32
  - 4S = - 56
 S, or cost of each small bottle = -56/-4 = $14