Question

Find the limit as h goes to 0 of the quotient of the quantity 5 times the square of the quantity x plus h, minus 2 minus the quantity 5 times x squared minus 2, and h.

5x^2 + h^2 + 7

10x

3x^2 – 2

10x – 2

Answer 1

10x

Explanation:

Answer 2

expand

`\lim_(h \to 0) (5(x^2+2hx+h^2)-2)-5x^2+2)/(h)`


`\lim_(h \to 0) (5x^2+10hx+5h^2-2-5x^2+2)/(h)`


`\lim_(h \to 0) (10hx+5h^2)/(h)`


`\lim_(h \to 0) 10x+5h`
say h=0 so
10x

answer is 2nd one