Question

What is the length (magnitude) of the vector (5,-2)?

Answer 1

5^2+(-2)^2=29
magnitude=(29)^(1/2)=around 5.3852

Answer 2

The magnitude of the given vector is
`√(29)`.

Explanation:

The magnitude of a vector v=<a,b> is defined as

`|v|=√(a^2+b^2)`

The given vector is

`v=<5,-2>`

The magnitude of the given vector is

`|v|=√(5^2+(-2)^2)`

`|v|=√(25+4)`

`|v|=√(29)`

Therefore the magnitude of the given vector is
`√(29)`.