How many grams of water are needed to dissolve 27.8 g of ammonium nitrate?

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asked Jul 9, 2018 56.4k views

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Frederix · Answer 1 · 2018-07-16T04:41:12+0000

The moles of ammonium nitrate needed to dissolve 0.35 moles
The moles of water that will react is 0.35 moles as due to ratio
so mass of water will be 0.35 x 18=6.3g
MASS OF WATER WILL BE 6.3 g

How many grams of water are needed to dissolve 27.8 g of ammonium nitrate?

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