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If n-^2 = 1/16, then n could be which of the following?

-8
-4
-1/4
1/4
4

1 Answer

4 votes

n^(-2)= \cfrac{1}{16} \\ \\ \cfrac{1}{n^2} = \cfrac{1}{16}; \ \ \ n \\eq 0 \\ \\ n^2=16 \\ \\ n=б √(16) \\ \\n=б4
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User Rajarshi
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