Explain your thinking process of all interferes between Square root of 12 and square root of 40

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asked Mar 23, 2018 177k views

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Ballmw · Answer 1 · 2018-03-27T19:32:46+0000

So since 3^2 = 9 < 12, 4^16 > 12, then 4 will be the first number of the sum

Since 6^2 = 36 < 40, 7^2 = 49 > 40, then 6 will be the last number of the sum

Therefore, the sum of integers is: 4+5+6 = 15

Explain your thinking process of all interferes between Square root of 12 and square root of 40

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