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Now consider lithium (LI+) and fluoride (F2) as oxidizing agents. How do these compare as oxidizing agents?
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Now consider lithium (LI+) and fluoride (F2) as oxidizing agents. How do these compare as oxidizing agents?
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Apr 19, 2018
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Now consider lithium (LI+) and fluoride (F2) as oxidizing agents. How do these compare as oxidizing agents?
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Answer:
Fluoride is a stronger oxidizing agent than lithium.
Step-by-step explanation:
Zfedoran
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Apr 22, 2018
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An oxidizing agent is a substance that oxidized the substance that oxidizes the substance it is reacting with and it is itself reduced.
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Which is the strongest oxidizing agent? lithium; li+ + e– → li e0 = –3.05 v hydrogen; 2h+ + 2e– → h2e0 = 0.00 v fluorine; f2 + 2e– → 2f–e0 = +2.87 v?
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