What is the equation in point-slope form of the line passing through (0, 5) and (−2, 11)? y − 5 = −3(x + 2) y − 5 = 3(x + 2) y − 11 = −3(x − 2) y − 11 = −3(x + 2)

Question

asked Jul 15, 2018 92.0k views

2 Answers

Gdoug · Answer 1 · 2018-07-17T18:29:31+0000

hello :

Hello : let A(0,5) B(-2,11)
the slope is : (YB - YA)/(XB -XA)
(11-5)/(-2-0) = 6/(-2)
the slope is : -3

the equation in point-slope form of the line is : y-11 = -3(x+2)

Maersu · Answer 2 · 2018-07-21T03:10:54+0000

Answer:
y-11=-3(x+2)

Explanation:

Given points : (0, 5) and (−2, 11)

Slope of the line passing through given points .

m=(y_2-y_1)/(x_2-x_1)=(11-5)/(-2-0)=(6)/(-2)=-3

Thus, slope of line passing through given points m=-3

We know that the equation of a line passing through points
(x_0,y_0) with slope 'm' is
(y-y_0)=m(x-x_0)

Thus, equation of a line passing through (−2, 11) with slope m=-3 will be

$(y-11)=(-3)(x-(-2))\\\Rightarrow\ y-11=-3(x+2)$

Hence, the equation of line is
y-11=-3(x+2)