Question

Complete the solution of the equation. find the value of y when x equals 11 8x+6y=28

Answer 1

First, substitute the value of x back into the equation.

8x + 6y = 28 becomes 8(11) + 6y = 28

Now solve for y.

8(11) + 6y = 28
88 + 6y = 28
6y = -60 <-- Subtract 88 from each side
y = -10 <-- Divide both sides by 6

So, y is equal to -10.

Answer 2

If x is 11, then we replace x with 11 in the equation.
8(11) + 6y = 28
88 + 6y = 28
We will subtract 88 from both sides to get rid of the constant.
6y = -60
To isolate the variable, we will divide both sides by 6.
y = -10
In this equation, y equals -10.