Use the quadratic formula to solve 3x^2-x+6=0

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asked Jul 17, 2018 148k views

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TermiT · Answer 1 · 2018-07-22T13:55:35+0000

x = ( -b +/- sqrt( b^2 - 4ac ) / 2a,

a = 3, b = -1, c= 6 in this particular case:

x = (1 +/- sqrt( 1 -72 ) ) / 6,

sqrt(-71) is imaginary. So no real solutions. If you haven't covered complex numbers, the answer is no solutions.

Use the quadratic formula to solve 3x^2-x+6=0

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