Answer:
D) A = 2p and B = 1/p
Explanation:
To divide this, we first see how many times 3p will go into 6p². It will go in 2p times; this goes up top of the problem.
Multiplying back through, we have
2p(3p) = 6p². Subtracting this from the first term under the box, we have
6p²-6p² = 0. This cancels. Bring down the next term, 9p.
See how many times 3p goes into 9p it goes in 3 times. This goes up top, beside the 2p. We separate them with a +, since the 3 is positive.
Multiplying back through, we have 3(3p) = 9p. Subtract this from the line above; 9p-9p = 0. Bring down the last term, 3. Since this is not 0, this is the remainder. This gives us
2p + 3 R 3; writing this as a rational expression, we have
2p + 3 + 3/3p
The remainder term, 3/3p, will simplify to 1/1p or 1/p; this gives us
2p + 3 + 1/p