Question

Identify the vertex and the y-intercept of the graph of the function y= -0.25(x-4)-2

Answer 1

The y intercept is -2, but I don't remember how to find the vertex sorry

Answer 2

the vertex is (4, -2) and y-intercept is -6

Explanation:

we need to identify the vertex and the y-intercept of the given function

`y=-0.25(x-4)^(2)-2`

Since, In general the equation of parabola

`y=a(x-h)^(2)+k` where (h,k) is vertex of parabola

Compare
`y=-0.25(x-4)^(2)-2` with
`y=a(x-h)^(2)+k`

so, the vertex is (4, -2)

and y-intercept is find by put x=0 in equation

`y=-0.25(0-4)^(2)-2`

`y=-0.25(4)^(2)-2`

`y=-0.25(16)-2`

`y=-4-2`

`y= -6`

Therefore, the vertex is (4, -2) and y-intercept is -6