I cannot make out the height along the left side. However this problem is quite simple, let s= that measurement along the left side vertical line. The area of this figure is just the area of a rectangle added to the area of a triangle...
A=(110*s)+(180-110)(s-50)/2
A=110s+35s-3500
A=(145s-3500) cm^2
...
The second problem is just a triangle:
A=4*6/2
A=12 cm^2