What is the following product? Assume d>/= 0

Question

asked Feb 2, 2018 148k views

2 Answers

Suhprano · Answer 1 · 2018-02-06T06:20:40+0000

Answer:

$\boxed{\boxed{\sqrt[3]{d}\cdot \sqrt[3]{d}\cdot \sqrt[3]{d}=d}}$

Explanation:

The given expression is,

$=\sqrt[3]{d}\cdot \sqrt[3]{d}\cdot \sqrt[3]{d}$

It can also be written as,

$=d^{(1)/(3)}\cdot d^{(1)/(3)}\cdot d^{(1)/(3)}$

The exponent product rule of algebra states that, while multiplying two powers that have the same base, the exponents can be added.

As here all the terms have same base i.e d, so applying the rule

$=d^{(1)/(3)+(1)/(3)+(1)/(3)}$

$=d^{(1+1+1)/(3)}$

$=d^{(3)/(3)}$

=d^1