Question

Given that mass was lost from the copper (ii) carbonate hydroxide hydrate during heating, in this decomposition reaction, how many moles of solid product were produced? the molar mass of the solid product is 79.545 g/mol (number of moles = mass (g) / molar mass (g/mol)).

Answer 1

0.0452

Step-by-step explanation:

Mass of product= final mass-mass of crucible

mass of product = 38.597g - 35.000g =3.597g

`product = (3.597g)/(79.545g/mol)`

Answer 2

the thermolysis of hydrate of the copper (II) hydroxycarbonate:

xCuCO₃·yCu(OH)₂·zH₂O → (x+y)CuO + xCO₂ + (y+z)H₂O

1 mol xCuCO₃·yCu(OH)₂·zH₂O → (x+y) mol CuO

for example, if x=y=1 ⇒ n(CuO)=2 mol