Question

Three consecutive integers have a sum of 78. what are the three integers?

Answer 1

n = first number
(n+1) = second number
(n+2) = third number

n + n+1 + n+2 = 78
3n + 3 = 78
3n + 78 - 3
3n = 75
n = 75/3
n = 25 first number
25 + 1 = 26 second number
25 + 2 = 27 third number

Check:
25 + 26 + 27 = 78

Answer 2

hello :
let Three consecutive integers : n , n+1 , n+2
n +n+1 +n+2 = 78
3n = 75
n = 75/3 = 25
the three integers are : 25 , 26 , 27