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`you've got gas! a sample of it that, is. more specifically, a 350.0 ml sample in an flexible container that has a temperature of 293.15 k. suppose you throw it on the stove and heat it to 373.15 k. what will the new volume be (in l)?

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User Publius
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1 Answer

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To solve this we assume that the gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant pressure and number of moles of the gas the ratio T/V is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

T1 / V1 = T2 / V2

V2 = T2 x V1 / T1

V2 = 373.15 x 350 / 293.15

V2 = 445.51 mL

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User WhoIsJack
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