Question

What is the distance between the points (4,5) and (10,13) on a coordinate plane?

Answer 1

10 units

Explanation:

Use the distance formula. (10-4)²+(13-5)²=100. The square root of 100 is 10.

Answer 2

the distacne between the points (x1,y1) and (x2,y2) is

`D=√((x_2-x_1)^2+(y_2-y_1)^2)`
so the distance between (4,5) and (10,13) is
well, first
x1=4
y1=5
x2=10
y2=13
so


`D=√((10-4)^2+(13-5)^2)`

`D=√((6)^2+(8)^2)`

`D=√(36+64)`
D=√100
D=10
the distance is 10 units