Question

A rectangular lot is 60 yards wide and 110 yards long. give the length and width of another rectangular lot that has the same perimeter but a smaller area.

Answer 1

P = 2(L + W)
P = 2(110 + 60)
P = 2(170)
P = 340

A = L * W
A = 110 * 60
A = 6600

so the perimeter is 340 and the area is 6600

same pyramid, smaller area..
L = 120
W = 50

P = 2(120 + 50)
P = 2(170)
P = 340....same perimeter

A = L * W
A = 120 * 50
A = 6000...smaller area

so the other rectangle can have a length of 120 yds and a width of 50 yds to have the same perimeter and a smaller area