asked 173k views
3 votes
Marianna average 84 on her first three history exams. The first score was 67 the second score was seven less than the third score. What did she score on the second and third exams?

asked
User Mustak
by
8.5k points

1 Answer

5 votes
Let S=score on the second exam, then
(67+S+(S+7))/3=84
cross multiply
2S+74=252
2S=178
S=89
So second exam: 89
third exam=89+7=96
Check: (67+89+96)/3=84 ok.
answered
User Rkagerer
by
8.9k points
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