Question

Simplify completely 40 v squared over 35 v to the fourth power divided by 20 v cubed over 5 v. 2 over 7 v to the fourth power 7 over 32 7 v to the fourth power over 2 32 over 7

Answer 1

(40v^2)/(35v^4) / (20v^3)/(5v)
(8)/(7v^2) / (4v^2/1)
(8)/(7v^2) * (1 / 4v^2)
2/(7v^4)

Answer 2

Given expression:
`(\left(40v^2\right))/(\left(35v^4\right))`÷\frac{\left(20v^3\right)}{\left(5v\right)}.

Changing division sign into multiplication and flipping the second fraction, we get

`(\left(40v^2\right))/(\left(35v^4\right))* (\left(5v\right))/(\left(20v^3\right))`

`\mathrm{Cancel\:the\:common\:factor:}\:5`

`=(8)/(7v^2)* (5v)/(20v^3)`

`\mathrm{Cancel\:the\:common\:factor\:again}\:5`

`=(8)/(7v^2)* (1)/(4v^2)`

`=(8)/(7* \:4v^2v^2)`

`=(8)/(28v^4)`

`\mathrm{Cancel\:the\:common\:factor:}\:4`

`=(2)/(7v^4)`

Therefore , correct option is
`(2)/(7v^4).`