Question

Which of the numbers below could be terms in the sequence an = 3n + 16? . Check all that apply. A. 61 B. 48 C. 46 D. 64

Answer 1

substitute every option by 16: A 45 B. 32 C 30 D 48
Apparently ACD are all multiples of 3, so they all apply

Answer 2

option B

Explanation:

an = 3n + 16

To identify the terms in the sequence we check with each option

A. 61

an = 3n + 16

61= 3n +6 (subtract 6 from both sides)

55= 3n (divide by 3 on both sides)

n =18.3 ( number of term cannot be a decimal)

B. 48

an = 3n + 16

48= 3n +6 (subtract 6 from both sides)

42= 3n (divide by 3 on both sides)

n =14 ( 48 is in 14th term)

C. 46

an = 3n + 16

46= 3n +6 (subtract 6 from both sides)

40= 3n (divide by 3 on both sides)

n =13.3 ( number of term cannot be a decimal)

D. 64

an = 3n + 16

64= 3n +6 (subtract 6 from both sides)

58= 3n (divide by 3 on both sides)

n =19.3 ( number of term cannot be a decimal)