Question

Betty scored 56 on a statistics test that had a mean of 65 and a standard deviation of 5. What was the Z- score on the test?

Answer 1

Z-score for a variable X is calculated using
Z(x)=(x-mean)/standard deviation.
Here
x=56
mean=65
standard deviation=5
so
Z(65)=(65-56)/5=9/5=1.8