asked 225k views
3 votes
For what value of b does (1/12)^2b x 12^-2b+2=12
-1/2
-1/4
1/4
no solution

asked
User Pramila
by
8.1k points

2 Answers

2 votes

Answer:

no solution

Explanation:

3 votes
the answer

first, the main properties are:

a^ -p = 1 /a^p
1 ^ b = 1, for all value of b

for solving the problem, we only apply the properties, that is

(1/12)^2b x 12^-2b+2= (1/12)^2b/12^2b + 2= [(1/12)^2/12^2]^b + 2 = 12

[1]^b + 2 = 12, finally 1 + 2 = 12, impossible

so the answer is no solution
answered
User Meriadec
by
8.1k points

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