Question

The sum of 3 consecutive integral numbers is 117. Find the numbers

Answer 1

Let the numbers be x, x+1, x+2
x+x+1+x+2=117
3x= 114
x= 38
they are 38,39,40

Answer 2

38,39 and 40

Explanation:

Given: the sum of 3 consecutive integral numbers is 117

To Find: Find the numbers.

Solution:

Let the three consecutive numbers be =
`\text{x}`

`\text{x}+1`

`\text{x}+2`

As given in question,

the sum of these three consecutive integral number is =
`117`

now,

`\text{x}+\text{x}+1+\text{x}+2=117`

`3\text{x}+3=117`

`3\text{x}=114`

`\text{x}=(114)/(3)`

`\text{x}=38`

first number is 38, other two numbers are

`\text{x}+1=39`

`\text{x}+2=40`

To verify,

`38+39+40=117`

Therefore three consecutive integrals whose sum is 117 are
`38,39` and
`40`