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What is the nuclear binding energy in joules for an atom of lithium? Assume the following: Mass defect = 6.9986235 × 10-29 kilograms. Use E = mc2, with c = 3 × 108 m/s.

What is the nuclear binding energy in joules for an atom of lithium? Assume the following: Mass defect = 6.9986235 × 10-29 kilograms. Use E = mc2, with c = 3 × 108 m/s.
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What is the nuclear binding energy in joules for an atom of lithium? Assume the following: Mass defect = 6.9986235 × 10-29 kilograms. Use E = mc2, with c = 3 × 108 m/s.

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User Whetstone
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2 Answers

2 votes

Answer:

A

Step-by-step explanation:

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User Rubish
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8.6k points
4 votes

The best answer is E=63 times 10^12

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User Nicolas NOEL
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7.9k points
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