asked 115k views
1 vote
HELP ANYONE TIMEDD

A sock drawer contains winter socks and summer socks. Both varieties come in two colors: red and blue. There are two pairs each of red summer socks and red winter socks, and one pair each of blue summer socks and blue winter socks. If a sock is selected randomly, what is the probability it will be a red sock or a winter sock?

HELP ANYONE TIMEDD A sock drawer contains winter socks and summer socks. Both varieties-example-1
HELP ANYONE TIMEDD A sock drawer contains winter socks and summer socks. Both varieties-example-1
HELP ANYONE TIMEDD A sock drawer contains winter socks and summer socks. Both varieties-example-2
HELP ANYONE TIMEDD A sock drawer contains winter socks and summer socks. Both varieties-example-3
HELP ANYONE TIMEDD A sock drawer contains winter socks and summer socks. Both varieties-example-4
asked
User Artharos
by
8.3k points

2 Answers

3 votes
4 red summer, 4 red winter, 2 blue summer, 2 blue winter
P(red) U P(winter) = 8/12 + 6/12 -4/12 =
10/12 = 5/6
answered
User Patricknelson
by
7.6k points
6 votes

If a sock is selected randomly, the probability that it will be a red sock or a winter sock is: D. 5/6.

Based on the information provided above, we can logically deduce that there are two (2) pairs each of red summer socks and red winter socks, and one pair each of blue summer socks and blue winter socks.

In this context, the total number of socks can be calculated as follows;

Total number of socks = 4 red summer + 4 red winter + 2 blue summer + 2 blue winter

Assuming a sock is randomly selected, the probability that it will be a red sock or a winter sock can be calculated as follows;

P(red) U P(winter) = (4/12 + 4/12) + (4/12 + 2/12) - 4/12

P(red) U P(winter) = 8/12 + 6/12 - 4/12

P(red) U P(winter) = 10/12

P(red) U P(winter) = 5/6.

answered
User Ben Haley
by
8.8k points
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