Question

How many moles of N are in 0.221 g of N2O?

Answer 1

no.of moles of N2O= 0.221g/(14*2+16) =0.005022727moles
no.of moles of N = 0.005022727*2 =0.010045454moles

Answer 2

0.221 g of
`N_2O` have 0.010 mol of N

Step-by-step explanation:

Mass of
`N_2O= 0.221\ g`

Step 1

Calculation of moles of
`N_2O`

`Mole=(Mass\ in\ g)/(Molecular\ mass)`

Molecular mass of
`N_2O` = 14 × 2 + 16 = 44

`Mole=(Mass\ in\ g)/(Molecular\ mass)`

`=(0.221)/(44) = 0.005\ mol`

Calculation of moles of N

1 mol of
`N_2O` has 2 moles of N

0.005 mol of
`N_2O` will have

= 0.005 × 2 = 0.010 mol of N

So, 0.221 g of
`N_2O` have 0.010 mol of N