Question

A 0.145 kg baseball is thrown from a platform above the ground at a 10 m/s. the ball is moving 15 m/s when it strikes the ground. from what height above the ground was the ball thrown? 6 m 10 m 1 m 5 m

Answer 1

v^2 = v0^2 + 2gh
2gh = v^2 - v0^2
h = (v^2 - v0^2)/2g
h = ((15 m/s)^2 - (10 m/s)^2)/2×9.81 m/s^2
h = (225 m^2/s^2 - 100 m^2/s^2)/19.62 m/s^2
h = 125 m^2/s^2/19.62 m/s^2
h = 6.37 m ≈ 6 m