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What are the x-intercepts of the function f(x) = –2x2 – 3x + 20?

1 Answer

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Function intercepts the x-axis where y=0


f(x) = y = -2x^2 -3x +20 \\ 0 = -2x^2-3x+20 \\

We can now calculate the discriminant and find the roots.


\Delta = (-3)^2 - 4\cdot(-2)\cdot(20) = 169 \\\\ \sqrt\Delta = 13\\\\ x_1 = (-(-3) - 13)/(2\cdot(-2)) = (5)/(2) \\\\ x_2 = (-(-3) + 13)/(2\cdot(-2)) = 4
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