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For what value of c is the function one-to one? {(1,2),(2,3)(3,5),(4,7),(5,11)(6,c)}

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User Rhlee
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2 Answers

4 votes

Final answer:

For the function to be one-to-one, the value of c must be any real number that is not already a y-value in the set, which means it cannot be 2, 3, 5, 7, or 11.

Step-by-step explanation:

The student is asking for the value of c that would make the given function one-to-one. A one-to-one function means that each x-value has a unique y-value. In the context of the provided set of ordered pairs, this means that to keep the function one-to-one, the y-value associated with x = 6 (which is c) must be different from any other y-values already present in the set.

The existing y-values are 2, 3, 5, 7, and 11. Therefore, c must be any value that is not already in the set of y-values. As a result, for the function to remain one-to-one, c can be any real number except 2, 3, 5, 7, and 11.

answered
User Meisyal
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8.7k points
2 votes
One to one function passes horizontal line test. If you plot function, it would looks like it increasing. at x=5, you have y=11 so at x=6, y should be greater than 11, right
answered
User Cristiana Chavez
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8.1k points

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