Question

Using the quadratic formula, what is the solution to 2x^2-5x-6=0 ?

Answer 1

`\bf \textit{quadratic formula}\\ \begin{array}{lcclll} 2x^2&-5x&-6&=0\\ \uparrow &\uparrow &\uparrow \\ a&b&c \end{array} \qquad \qquad x= \cfrac{ - {{ b}} \pm \sqrt { {{ b}}^2 -4{{ a}}{{ c}}}}{2{{ a}}}\\\\ -----------------------------\\\\ x=\cfrac{-(-5)\pm√((-5)^2-4(2)(-6))}{2(2)}\implies x=\cfrac{5\pm√(25+48)}{4} \\\\\\ x=\cfrac{5\pm√(73)}{4}\implies x= \begin{cases} \cfrac{5+√(73)}{4}\\\\ \cfrac{5-√(73)}{4} \end{cases}`