Question

What is the difference (x/x^2+3x+2)-(1/(x+2)(x+1)

a. (x-1)/(6x+4)
b. (-1)/4x+2)
c. (1)/(x+2)
d. (x-1)/x^2+3x+2)

Answer 1

Option D is correct

The difference of
`(x)/(x^2+3x+2)- (1)/((x+2)(x+1))` =
`(x-1)/(x^2+3x+2)`

Explanation:

To find the difference of the equation:

`(x)/(x^2+3x+2)- (1)/((x+2)(x+1))` ....[1]

first multiply the terms

`(x+2)(x+1) =(x^2+x+2x+2)`

Substitute this in equation [1], we have

`(x)/(x^2+3x+2)- (1)/(x^2+3x+2)`

If the denominators are same, then we have

`(x+(-1))/(x^2+3x+2)` =
`(x-1)/(x^2+3x+2)`

Therefore, the difference of the given equation
`(x)/(x^2+3x+2)- (1)/((x+2)(x+1))` is,
`(x-1)/(x^2+3x+2)`

Answer 2

answer is D i believe