What are the lengths of the legs of a triangle in which one acute angle measures 19 degrees and the hypotenuse is 15 units long?

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asked Jun 1, 2018 194k views

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Marcel Preda · Answer 1 · 2018-06-07T11:47:12+0000

sin (19°) = side a / 15
side a = 15 * sin (19°)
side a = 15 * 0.32557
side a = 4.88355

side b^2 = 15^2 - 4.88355^2
side b^2 = 225 - 23.8490606025
side b^2 = 201.15
side b = 14.18

What are the lengths of the legs of a triangle in which one acute angle measures 19 degrees-example-1

What are the lengths of the legs of a triangle in which one acute angle measures 19 degrees and the hypotenuse is 15 units long?

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