Question

A population of 500 animals that decreases at an annual rate of 17%

Answer 1

This is exponential decay of the form:

f=ir^t, f=final amount, i=initial amount, r=rate, t=time in this case:

p(t)=500((100-17)/100)^t

p(t)=500(0.83)^t

Answer 2

Answer : 0.17

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