A plane is flying at an altitude of 12,000 feet and is preparing to land at a nearby airport. The angle from the airport to the plane is 17°. To the nearest tenth of a foot, how…

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asked Nov 10, 2018 214k views

2 Answers

Simo Mafuxwana · Answer 1 · 2018-11-14T21:01:06+0000

Answer: The airport is 41043.6 feet far away from the plane.

Explanation:

Since we have given that

A plane is flying at an altitude of 12,000 feet

As shown in the figure :

AB = 12000 feet

and the angle of elevation from the airport to the plane = 17 °

Consider, ΔABC ,

$\sin 17^\circ=(AB)/(AC)\\\\\sin 17^\circ=(12000)/(AC)\\\\AC=(12000)/(\sin 17^\circ)\\\\BC=41043.64\ feet$

Hence, the airport is 41043.6 feet far away from the plane.