Question

What is the molarity of a 2.0 liter solution containing 58 grams of nacl?

Answer 1

To calculate the molarity of a 2.0 liter solution containing 58 grams of NaCl, convert the mass of NaCl to moles using its molar mass (58.44 g/mol) and then divide by the volume of the solution in liters to obtain a molarity of approximately 0.4964 M.

Step-by-step explanation:

The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. To find the molarity of a 2.0 liter solution containing 58 grams of NaCl, we first need to convert grams to moles. The molar mass of NaCl (sodium chloride) is 58.44 g/mol. Thus, we have:

• Number of moles of NaCl = 58 g / 58.44 g/mol = 0.9928 mol (approximately)
• Molarity (M) = moles of solute / liters of solution = 0.9928 mol / 2.0 L = 0.4964 M (approximately)

So, the molarity of the NaCl solution is approximately 0.4964 M.

Answer 2

1.000 mol NaCl/2.00 L soln = 0.500 M NaCl

Step-by-step explanation:

answer should be reported with three significant figures because each piece of data had three or more significant figures.