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What is the minimum value for for h(x)=x^2−16x+60?

What is the minimum value for for h(x)=x^2−16x+60?
asked 75.3k views
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What is the minimum value for for h(x)=x^2−16x+60?

What is the minimum value for for h(x)=x^2−16x+60?-example-1
asked
User FXQuantTrader
by
7.5k points

1 Answer

3 votes
dy/dx = 2x - 16 =0 (for h(x) to be minimum)

x=8

h(8)= - 4
answered
User Miguel Marques
by
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