Question

Suppose you choose a marble from a bag containing 2 red marbles, 5 white marbles and 3 blue marbles. You return the first marble to the bag and choose again. Find p (red then blue)

Answer 1

I think it would be 2/10 x 3/10=6/100=3/50

Answer 2

Answer:
`(3)/(50)`

Explanation:

Given: Number of red marbles = 2

Number of white marbles = 5

Number of blue marbles = 3

Total marbles =2+5+3=10

If we choose first marble from the bag, then the probability of having red marbles will be :-

`P(R)=(2)/(10)=(1)/(5)`

If we choose second marble after replacement (total remains same) from the bag, then the prob ability of having blue marbles will be :-

`P(B)=(3)/(10)`

Since, both the events are independent.

Therefore, the probability of choosing red marble then blue marble is given by :-

`\text{P(red then blue)}=P(R)* P(B)=(1)/(5)*(3)/(10)=(3)/(50)`