Question

Use the quadratic formula to determine the exact solutions to the equation. 2x^2−5x+1=0

Answer 1

`2x^2-5x+1=0`

`x=(-b\pm√(b^2-4ac))/(2a)`

`x=(5\pm√(25-8))/(4)=(5\pm√(17))/(4)=(5-√(17))/(4),(5+√(17))/(4)`


`x_1=(5-√(17))/(4)`

`x_2=(5+√(17))/(4)`

:)