Question

At constant pressure, 492 mL of a gas at 31.00C is heated and the volume expands to 876mL. What is the new temperature in Kelvin?

A) 171 K
B) 291 K
C) 328 K
D) 541 K

Answer 1

The answer should be B........

Answer 2

Answer: Option (D) is the correct answer.

Step-by-step explanation:

It is given that pressure is constant and the given data is as follows.

`V_(1)` = 492 mL,
`T_(1)` = 31 + 273 = 304 K

`V_(2)` = 876 mL,
`T_(2)` = ?

Therefore, calculate the temperature
`T_(2)` as follows.

`(PV_(1))/(T_(1)) = (PV_(2))/(T_(2))`

Since pressure is constant so, value of P = 1.

`(V_(1))/(T_(1)) = (V_(2))/(T_(2))`

`T_(2) = (V_(2)T_(1))/(V_(1))`

=
`(876 mL * 304 K)/(492 mL)`

= 541.268 K

= 541 K (approx)

Thus, we can conclude that value of
`T_(2)` is 541 K.