Question

When 80 g of sodium hydroxide, naoh, are dissolved in enough water to make 500 ml of solution, the molarity of the solution is?

Answer 1

The molarity of the solution formed by dissolving 80 g of NaOH in 500 mL of water is 4 M, calculated by dividing the number of moles of NaOH (2 mol) by the volume of the solution in liters (0.5 L).

Step-by-step explanation:

To calculate the molarity of a solution, we use the following steps:

1. Convert the mass of the solute to moles by dividing by the molar mass of the compound.
2. Convert the volume of the solution from milliliters to liters.
3. Divide the number of moles by the volume in liters to find the molarity.

Given a mass of 80 g of NaOH and the molar mass of NaOH which is 40.0 g/mol, we can find the number of moles of NaOH:

Moles of NaOH = 80 g ÷ 40.0 g/mol = 2 mol

Next, we convert the volume of the solution from milliliters to liters:

500 mL × 1 L/1000 mL = 0.5 L

Finally, we calculate the molarity (M) as follows:

Molarity = Moles of solute ÷ Volume of solution in liters

Molarity = 2 mol ÷ 0.5 L = 4 M

Answer 2

What is the molarity of a solution that contains 80.0 grams of NaOH dissolved in 500 mL of solution? Student prepares a solution by dissolving 3.72 g of NaOH in enough water to make 300.