Question

PLEASE HELP! MATH

Simplify completely the quantity 6 times x to the 4th power plus 9 times x to the 2nd power plus 12 times x all over 3 times x.

A. 2x3 + 9x2 + 12
B. 2x2 + 3x + 4
C. 2x5 + 3x3 + 4x2
D. 2x3 + 3x + 4

Answer 1

6x^4+9x^2+12x/3x = 2x^3+3x+4

So the answer is D. 2x3 + 3x + 4

Answer 2

D)
`2x^(3) +3x + 4`.

Explanation:

Given : quantity 6 times x to the 4th power plus 9 times x to the 2nd power plus 12 times x all over 3 times x.

To find : Simplify completely the quantity.

Solution : We have given that a statement .

According to question:

6 times x to the 4th power =
`6x^(4)`.

9 times x to the 2nd power =
`9x^(2)`.

12 times x = 12x.

`6x^(4)` +
`9x^(2)` + 12x over 3x.

`(6x^(4))/(3x) +(9x^(2))/(3x) +(12x)/(3x)`.

On dividing we get ,

`2x^(3) +3x + 4`.

Therefore, D)
`2x^(3) +3x + 4`.