Question

Find the angle there with sectheta=2 exactly over 0

Answer 1

`\bf sec(\theta)=\cfrac{2}{0}\iff \cfrac{1}{cos(\theta)}=\cfrac{2}{0}\implies \cfrac{1\cdot 0}{2}=cos(\theta)\implies cos^(-1)(0)=\theta \\\\\\ \theta= \begin{cases} (\pi )/(2)\\\\ (3\pi )/(2) \end{cases}`

on the interval [0, 2π]