Question

Consider the Zn(s) + Cu+2(aq) + Zn+2(aq) +Cu(s) system.

Which element was the electron donor?

Answer 1

The electron donor in the reaction is the Zn and as a result it is oxidised to Zn²⁺. A move from an oxidation state of 0 to 2 (Oxidation is the Loss of Electron)

Answer 2

Answer: Zinc element was the electron donor

Step-by-step explanation:

`Zn(s)+Cu+2(aq)\rightarrow Zn^(+2)(aq)+Cu(s)`

In the given reaction, the zinc metal is getting oxidized to zinc ion by loosing 2 electrons and copper ion are getting reduced to copper by gaining 2 electrons.

`Zn\rightarrow Zn^(2+)+2e^-`

`Cu^(2+)+2e^-\rightarrow Cu`

So, in the given reaction zinc is an element which donates its electrons.Hence, electron donor was the zinc element.