Question

ツ---Graph y=-x^2-2. Identify the vertex of the graph.Tell whether it is a minimum or maximum.---ツ

A.) (0, –2); minimum
B.) (–2, 0); minimum
C.) (0, –2); maximum
D.) (–2, 0); maximum

Answer 1

Hey!

Hope this Helps...

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Below, I added what the graph of (x^2)-2 looks like...

The answer is A. (0, -2); Minimum

Answer 2

the correct answer is option C because it is maximum at (0,-2)

Explanation:

given equation,

y = -x² -2

to find maxima and minima we will differentiate the equation

`\frac{\mathrm{d} y}{\mathrm{d} x}=-x^2-2`

`\frac{\mathrm{d} y}{\mathrm{d} x}=-2x\\\frac{\mathrm{d} y}{\mathrm{d} x}=-2`

hence we can see that double differentiation is - ve so the equation will maximum.

hence, now putting value from option C

the value of y comes out to be -2

now, putting value from option D

value of y comes out to be -6

hence, the correct answer is option C because it is maximum at (0,-2)