asked 186k views
1 vote
Two spherical balloons are filled with water. The first balloon has a radius of 3 cm, and the second has a radius of 6 cm.

How much greater is the volume of water in the larger balloon than in the smaller balloon?

Use 3.14 to approximate pi. Round to the nearest hundredth if necessary.

Enter your answer in the box.

cm³

asked
User Robenson
by
7.8k points

2 Answers

5 votes
all you do to calculate the volume is 4/3*3.14*r^3
answered
User B L
by
8.2k points
3 votes

Answer:

Answer is 791.28
cm^(3)

Explanation:

First we need to calculate the volume of each balloons by using the formula

volume of sphere with radius r is

V = 4/3 π
r^(3)

Balloon 1.

r1 = 3 cm

V1 = 4/3 × 3.14 ×
3^(3)

V1 = 113.04
cm^(3)

Balloon 2.

r2 = 6 cm

V2 = 4/3 × 3.14 ×
6^(3)

V2 = 904.32
cm^(3)

Therefore we subtract small volume of balloon from large volume of balloon

= V2 - V1

= 904.32
cm^(3) - 113.04
cm^(3)

= 904.32 - 113.04 = 791.28
cm^(3)

answered
User Ander Webbs
by
8.4k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.