Question

 Squares are built at the sides of the rectangle. The area of one square is 95 cm2 greater that the area of the other square. Find the perimeter of the rectangle if the length of it is 5 cm greater than its width.

Answer 1

I hope this helps you



length = w+5



width = w



Area = width × length 95


95


w=8



95 <8. (8+5)



95 <8.13


95 <104



Perimeter =2 (width +length )



Perimeter =2. (8+13)



Perimeter =42

Answer 2

38 cm

Explanation:

The large square = y+95

Smaller square = y

rectangle width = x

rectangle length = x+5

Area of large square: (x+5)^2=y+95

Area of small square: x^2 = y

After some algebra: x=7, y=49

Length of rectangle: 7+5 = 12

Width of rectangle: x = 5

Perimeter = 2(12) + 2(5) = 38 cm