asked 204k views
4 votes
a rock is thrown straight up into the air from a height of 4 feet. the height of the rock above the ground, in feet, t seconds after it is thrown is given by -16t^2+56t+4. for how many seconds will the height of the rock be at least 28 feet above the ground?

1 Answer

5 votes
18 is the answe skikiii
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